2019年1月26日 · The photoelectric effect does not involve electron-electron scattering but photon electron scattering, the photon transferring energy to the ejected electron. The introduction of a macroscopic voltage cannot change the atomic structure and consequently the band structure of the energy levels of the electrons at the surface.

2017年2月20日 · If the photoelectric effect was explained in terms of wave theory. Then the energy of wave of incident light will not go to any particular electron but will be distributed to all electrons present on the illuminated surface. The time delay would have been much larger than experimental time lag(10^-9 s).

2015年12月23日 · In the photoelectric experiment, when light, having frequency greater than the threshold frequency, falls on a metal, electrons are emitted. Since electrons emitted are of different energies (I presume it's because they're coming from different energy levels in the lattice of the metal), not all of them are able to reach the anode per second .

2023年12月1日 · The photoelectric effect was discovered before Bohr came up with its Bohr model (energy levels, etc.) When a photon of the right frequency ##f> f_0## hits a metal and ejects an electron, that electron was previously bound to a metal atom.

2014年10月23日 · There are certain conclusions that can be explained by quantum physics about the photoelectric effect: 1) photoelectrons only emitted if frequency>threshold frequency and hence energy of photon> work function 2)Increasing intensity increases no. of photons (and thus photoelectrons provided f>f0...

The premise of your question is false. The photoelectric effect will occur whenever radiation interacts with the bounds electrons of an atom. There is a sharp increase in absorption when the energy of the radiation exceeds the binding energy of a particular "shell". For Rb, for example, the NIST XCOM database shows clear K and L edges:

2016年3月21日 · Well intensity refers to the number of photons. In that graph. The intensity of light is the same for all 3 frequencies.

2016年1月18日 · Books says time lag in which an electron leave atom, in photoelectric effect, is negligible. Is this negligible value been calculated?

2013年2月11日 · In the photoelectric effect, there is at most one photon is destroyed for every electron that is emitted by the surface. Some of the photons may be destroyed by processes other than the photoelectric effect. In an academic exercise or school test, I …

In the photoelectric effect however the photon seems to give all it's momentum and energy to the electron? No, the photoelectrons are emitted with a range of energies. The well known expression: $$ E = h\nu - \phi $$ gives the maximum energy, but photoelectrons are emitted with energies ranging from zero to this maximum value.